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跳出多重循环

news 2025/6/14 16:12:55

跳出多重循环

示例——用1角、2角、5角凑出一个预设的以元为单位的金额（要求整数元）

#include <stdio.h>
int main()
{int x;int one, two, five;printf("请输入需要的金额：");scanf("%d", &x);for (one = 1; one < x * 10; one++){for (two = 1; two < x * 10 / 2; two++){for (five = 1; five < x * 10 / 5; five++){if (one * 1 + two * 2 + five * 5 == x * 10){printf("可以使用%d个1角+%d个2角+%d个5角得到%d元\n", one, two, five, x);}}}}return 0;
}

输入想要的金额（元）后，以上程序会输出所有组合。在实际应用中，如果我们只需要一个组合结果的话，可以在程序中加入代码，跳出多重循环

方法一
接力break (注意：break和continue只针对它所在的这个循环，单纯加上一条break只能跳出当前循环，回到上一级循环)

#include <stdio.h>
int main()
{int x;int exit = 0;int one, two, five;printf("请输入需要的金额：");scanf("%d", &x);for (one = 1; one < x * 10; one++){for (two = 1; two < x * 10 / 2; two++){for (five = 1; five < x * 10 / 5; five++){if (one * 1 + two * 2 + five * 5 == x * 10){printf("可以使用%d个1角+%d个2角+%d个5角得到%d元\n", one, two, five, x);exit = 1;break;}}if (exit == 1)break;}if (exit == 1)break;}return 0;
}

因为break只是跳出当前循环，所以加上一个变量exit,配合if判断跳出外面的两重循环。

方法二 goto

#include <stdio.h>
int main()
{int x;int one, two, five;printf("请输入需要的金额：");scanf("%d", &x);for (one = 1; one < x * 10; one++){for (two = 1; two < x * 10 / 2; two++){for (five = 1; five < x * 10 / 5; five++){if (one * 1 + two * 2 + five * 5 == x * 10){printf("可以使用%d个1角+%d个2角+%d个5角得到%d元\n", one, two, five, x);goto end;}}}}
end:return 0;
}