A Bug's Life
sex保存异性，（a,b) 同性的在一个集合，a一定和sex[b]是同性的，b一定和sex[a]是同性的。
| Problem Description Background Professor Hopper is researching the sexual behavior of a rare species of bugs. He assumes that they feature two different genders and that they only interact with bugs of the opposite gender. In his experiment, individual bugs and their interactions were easy to identify, because numbers were printed on their backs. Problem Given a list of bug interactions, decide whether the experiment supports his assumption of two genders with no homosexual bugs or if it contains some bug interactions that falsify it. |
| Input The first line of the input contains the number of scenarios. Each scenario starts with one line giving the number of bugs (at least one, and up to 2000) and the number of interactions (up to 1000000) separated by a single space. In the following lines, each interaction is given in the form of two distinct bug numbers separated by a single space. Bugs are numbered consecutively starting from one. |
| Output The output for every scenario is a line containing "Scenario #i:", where i is the number of the scenario starting at 1, followed by one line saying either "No suspicious bugs found!" if the experiment is consistent with his assumption about the bugs' sexual behavior, or "Suspicious bugs found!" if Professor Hopper's assumption is definitely wrong. |
| Sample Input 2 3 3 1 2 2 3 1 3 4 2 1 2 3 4 |
| Sample Output Scenario #1: Suspicious bugs found!Scenario #2: No suspicious bugs found! |
| Source TUD Programming Contest 2005, Darmstadt, Germany |
| Recommend linle |
#include<iostream>
using namespace std;
int bugs[4004];
int sex[2002];
bool isfind=false;
void init(int n)
{
for(int i=1;i<=n;i++)
{
bugs[i]=-1;
sex[i]=0;
}
isfind=false;
}
int parent(int a)
{
while(bugs[a]>0)
{
a=bugs[a];
}
return a;
}
void combine(int a,int b)
{
int p1=parent(a);
int p2=parent(b);
if(p1!=p2)
{
if(bugs[p1]>bugs[p2])
{
bugs[p1]=p2;
bugs[p2]--;
}
else
{
bugs[p2]=p1;
bugs[p1]--;
}
}
}
void equal(int a,int b)
{
int p1=parent(a);
int p2=parent(b);
if(p1==p2)
{
isfind=true;
return;
}
if(sex[a])combine(sex[a],b);
if(sex[b])combine(sex[b],a);
sex[a]=b;
sex[b]=a;
}
int main()
{
//freopen("in.txt","r",stdin);
int n;
scanf("%d",&n);
int icase=1;
while(n--)
{
printf("Scenario #%d:\n",icase++);
int num,inter;
scanf("%d%d",&num,&inter);
init(num);
for(int i=1;i<=inter;i++)
{
int a,b;
scanf("%d%d",&a,&b);
if(!isfind)
{
equal(a,b);
}
else{
continue;
}
}
if(isfind)
{
printf("Suspicious bugs found!\n");
}
else
{
printf("No suspicious bugs found!\n");
}
printf("\n");
}
return 0;
}