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【C++】SDL2环境安装及AI编码简单的俄罗斯方块游戏

ai 2025/7/21 2:29:04

AI时代编码及文档功能

SDL2环境安装

Windows系统安装方法
下载SDL2开发库从官网（https://www.libsdl.org/download-2.0.php），选择SDL2-devel-2.0.x-mingw.tar.gz（MinGW）或SDL2-devel-2.0.x-VC.zip（Visual Studio）。解压后将以下文件复制到对应目录：

include文件夹内容 → 编译器头文件目录（如C:\MinGW\include\SDL2）
lib文件夹内容 → 编译器库目录（如C:\MinGW\lib）
SDL2.dll → 项目输出目录或系统C:\Windows\System32

Linux系统安装方法
通过包管理器直接安装：

sudo apt-get install libsdl2-dev  # Debian/Ubuntu
sudo yum install SDL2-devel       # CentOS/Fedora

macOS系统安装方法
使用Homebrew安装：

brew install sdl2

项目配置示例（CMake）

创建CMakeLists.txt文件，添加SDL2依赖：

cmake_minimum_required(VERSION 3.10)
project(Tetris)
find_package(SDL2 REQUIRED)
add_executable(tetris main.cpp)
target_include_directories(tetris PRIVATE ${SDL2_INCLUDE_DIRS})
target_link_libraries(tetris ${SDL2_LIBRARIES})

简单俄罗斯方块实现代码框架

初始化SDL2窗口与渲染器

#include <SDL2/SDL.h>
#include <vector>const int GRID_WIDTH = 10;
const int GRID_HEIGHT = 20;
const int CELL_SIZE = 30;SDL_Window* window = nullptr;
SDL_Renderer* renderer = nullptr;bool init() {if (SDL_Init(SDL_INIT_VIDEO) < 0) return false;window = SDL_CreateWindow("Tetris", SDL_WINDOWPOS_CENTERED, SDL_WINDOWPOS_CENTERED, GRID_WIDTH * CELL_SIZE, GRID_HEIGHT * CELL_SIZE, 0);renderer = SDL_CreateRenderer(window, -1, SDL_RENDERER_ACCELERATED);return window && renderer;
}

定义方块形状
使用4x4矩阵表示7种经典方块：

std::vector<std::vector<std::vector<int>>> SHAPES = {{{1,1,1,1}, {0,0,0,0}}, // I{{1,1}, {1,1}},         // O{{0,1,1}, {1,1,0}}      // Z// 添加其他形状...
};

游戏主循环逻辑

void gameLoop() {bool running = true;SDL_Event e;while (running) {while (SDL_PollEvent(&e)) {if (e.type == SDL_QUIT) running = false;if (e.type == SDL_KEYDOWN) {switch (e.key.keysym.sym) {case SDLK_LEFT:  moveCurrentPiece(-1); break;case SDLK_RIGHT: moveCurrentPiece(1);  break;case SDLK_DOWN:  dropPiece();          break;}}}SDL_SetRenderDrawColor(renderer, 0, 0, 0, 255);SDL_RenderClear(renderer);renderGrid();SDL_RenderPresent(renderer);}
}

碰撞检测实现

bool checkCollision(const std::vector<std::vector<int>>& grid, int x, int y) {for (int i = 0; i < 4; ++i) {for (int j = 0; j < 4; ++j) {if (currentPiece[i][j] && (x + j < 0 || x + j >= GRID_WIDTH || y + i >= GRID_HEIGHT || grid[y + i][x + j])) {return true;}}}return false;
}